13123450010051 has 2 divisors, whose sum is σ = 13123450010052. Its totient is φ = 13123450010050.

The previous prime is 13123450010029. The next prime is 13123450010053. The reversal of 13123450010051 is 15001005432131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13123450010051 - 2¹⁸ = 13123449747907 is a prime.

Together with 13123450010053, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13123450010051.

It is not a weakly prime, because it can be changed into another prime (13123450010053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561725005025 + 6561725005026.

It is an arithmetic number, because the mean of its divisors is an integer number (6561725005026).

Almost surely, 2^{13123450010051} is an apocalyptic number.

13123450010051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123450010051 is an equidigital number, since it uses as much as digits as its factorization.

13123450010051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 13123450010051 its reverse (15001005432131), we get a palindrome (28124455442182).

The spelling of 13123450010051 in words is "thirteen trillion, one hundred twenty-three billion, four hundred fifty million, ten thousand, fifty-one".