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131236451189 is a prime number
BaseRepresentation
bin111101000111001001…
…1010101001101110101
3110112202002112110210022
41322032103111031311
54122233012414224
6140142244334525
712324106300214
oct1721623251565
9415662473708
10131236451189
1150725612218
12215269a4445
13c4b60bc45c
1464cd7a707b
15363169e65e
hex1e8e4d5375

131236451189 has 2 divisors, whose sum is σ = 131236451190. Its totient is φ = 131236451188.

The previous prime is 131236451149. The next prime is 131236451219. The reversal of 131236451189 is 981154632131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110562900100 + 20673551089 = 332510^2 + 143783^2 .

It is an emirp because it is prime and its reverse (981154632131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131236451189 - 228 = 130968015733 is a prime.

It is a super-2 number, since 2×1312364511892 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131236451149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65618225594 + 65618225595.

It is an arithmetic number, because the mean of its divisors is an integer number (65618225595).

Almost surely, 2131236451189 is an apocalyptic number.

It is an amenable number.

131236451189 is a deficient number, since it is larger than the sum of its proper divisors (1).

131236451189 is an equidigital number, since it uses as much as digits as its factorization.

131236451189 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 44.

The spelling of 131236451189 in words is "one hundred thirty-one billion, two hundred thirty-six million, four hundred fifty-one thousand, one hundred eighty-nine".