1312404213301 has 4 divisors (see below), whose sum is σ = 1344414072204. Its totient is φ = 1280394354400.

The previous prime is 1312404213287. The next prime is 1312404213311. The reversal of 1312404213301 is 1033124042131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 46668960900 + 1265735252401 = 216030^2 + 1125049^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312404213301 - 2⁵ = 1312404213269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312404213311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16004929390 + ... + 16004929471.

It is an arithmetic number, because the mean of its divisors is an integer number (336103518051).

Almost surely, 2^{1312404213301} is an apocalyptic number.

It is an amenable number.

1312404213301 is a deficient number, since it is larger than the sum of its proper divisors (32009858903).

1312404213301 is an equidigital number, since it uses as much as digits as its factorization.

1312404213301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32009858902.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1312404213301 its reverse (1033124042131), we get a palindrome (2345528255432).

The spelling of 1312404213301 in words is "one trillion, three hundred twelve billion, four hundred four million, two hundred thirteen thousand, three hundred one".