Base | Representation |
---|---|
bin | 11000011100100001… |
… | …00011110111111101 |
3 | 1020212122100120210111 |
4 | 30032100203313331 |
5 | 203334233433112 |
6 | 10010143310021 |
7 | 643141133434 |
oct | 141620436775 |
9 | 36778316714 |
10 | 13124124157 |
11 | 5625253801 |
12 | 26632ab311 |
13 | 1312010b51 |
14 | 8c703a11b |
15 | 51c2be5a7 |
hex | 30e423dfd |
13124124157 has 2 divisors, whose sum is σ = 13124124158. Its totient is φ = 13124124156.
The previous prime is 13124124119. The next prime is 13124124161. The reversal of 13124124157 is 75142142131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7713933241 + 5410190916 = 87829^2 + 73554^2 .
It is a cyclic number.
It is not a de Polignac number, because 13124124157 - 227 = 12989906429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124122157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562062078 + 6562062079.
It is an arithmetic number, because the mean of its divisors is an integer number (6562062079).
Almost surely, 213124124157 is an apocalyptic number.
It is an amenable number.
13124124157 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124124157 is an equidigital number, since it uses as much as digits as its factorization.
13124124157 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6720, while the sum is 31.
Adding to 13124124157 its reverse (75142142131), we get a palindrome (88266266288).
The spelling of 13124124157 in words is "thirteen billion, one hundred twenty-four million, one hundred twenty-four thousand, one hundred fifty-seven".
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