Base | Representation |
---|---|
bin | 111101000111010010… |
… | …1111000100010000101 |
3 | 110112202102200112220121 |
4 | 1322032211320202011 |
5 | 4122240234030222 |
6 | 140142540501541 |
7 | 12324165523612 |
oct | 1721645704205 |
9 | 415672615817 |
10 | 131241314437 |
11 | 50728334032 |
12 | 2152854a8b1 |
13 | c4b7102c0c |
14 | 64d02b1509 |
15 | 3631d105c7 |
hex | 1e8e978885 |
131241314437 has 2 divisors, whose sum is σ = 131241314438. Its totient is φ = 131241314436.
The previous prime is 131241314411. The next prime is 131241314447. The reversal of 131241314437 is 734413142131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95623811361 + 35617503076 = 309231^2 + 188726^2 .
It is a cyclic number.
It is not a de Polignac number, because 131241314437 - 215 = 131241281669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131241314447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65620657218 + 65620657219.
It is an arithmetic number, because the mean of its divisors is an integer number (65620657219).
Almost surely, 2131241314437 is an apocalyptic number.
It is an amenable number.
131241314437 is a deficient number, since it is larger than the sum of its proper divisors (1).
131241314437 is an equidigital number, since it uses as much as digits as its factorization.
131241314437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24192, while the sum is 34.
Adding to 131241314437 its reverse (734413142131), we get a palindrome (865654456568).
The spelling of 131241314437 in words is "one hundred thirty-one billion, two hundred forty-one million, three hundred fourteen thousand, four hundred thirty-seven".
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