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13124140404421 is a prime number
BaseRepresentation
bin1011111011111011001110…
…1110100000111011000101
31201110122200220120110212211
42332332303232200323011
53210011214420420141
643525051420143421
72523121301543614
oct276766356407305
951418626513784
1013124140404421
1141aaa0a126a52
12157b668097b71
137427a78b3617
143352d71cd87b
1517b5c7d98d81
hexbefb3ba0ec5

13124140404421 has 2 divisors, whose sum is σ = 13124140404422. Its totient is φ = 13124140404420.

The previous prime is 13124140404383. The next prime is 13124140404443. The reversal of 13124140404421 is 12440404142131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12858929824225 + 265210580196 = 3585935^2 + 514986^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124140404421 - 219 = 13124139880133 is a prime.

It is a super-2 number, since 2×131241404044212 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124140404461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562070202210 + 6562070202211.

It is an arithmetic number, because the mean of its divisors is an integer number (6562070202211).

Almost surely, 213124140404421 is an apocalyptic number.

It is an amenable number.

13124140404421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124140404421 is an equidigital number, since it uses as much as digits as its factorization.

13124140404421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 13124140404421 its reverse (12440404142131), we get a palindrome (25564544546552).

The spelling of 13124140404421 in words is "thirteen trillion, one hundred twenty-four billion, one hundred forty million, four hundred four thousand, four hundred twenty-one".