Base | Representation |
---|---|
bin | 1011111011111011001111… |
… | …0100101100011000011111 |
3 | 1201110122201000121202211111 |
4 | 2332332303310230120133 |
5 | 3210011220324233343 |
6 | 43525051515002451 |
7 | 2523121321401226 |
oct | 276766364543037 |
9 | 51418630552744 |
10 | 13124142024223 |
11 | 41aaa10032a2a |
12 | 157b668739427 |
13 | 7427a802c999 |
14 | 3352d74d1cbd |
15 | 17b5c80b8c9d |
hex | befb3d2c61f |
13124142024223 has 2 divisors, whose sum is σ = 13124142024224. Its totient is φ = 13124142024222.
The previous prime is 13124142024199. The next prime is 13124142024233. The reversal of 13124142024223 is 32242024142131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13124142024223 - 237 = 12986703070751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124142024233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562071012111 + 6562071012112.
It is an arithmetic number, because the mean of its divisors is an integer number (6562071012112).
Almost surely, 213124142024223 is an apocalyptic number.
13124142024223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124142024223 is an equidigital number, since it uses as much as digits as its factorization.
13124142024223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 13124142024223 its reverse (32242024142131), we get a palindrome (45366166166354).
The spelling of 13124142024223 in words is "thirteen trillion, one hundred twenty-four billion, one hundred forty-two million, twenty-four thousand, two hundred twenty-three".
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