Base | Representation |
---|---|
bin | 1011111011111011011101… |
… | …0110111000111011001101 |
3 | 1201110122212011012022112121 |
4 | 2332332313112320323031 |
5 | 3210011331014221031 |
6 | 43525101433532541 |
7 | 2523122641403512 |
oct | 276766726707315 |
9 | 51418764168477 |
10 | 13124201320141 |
11 | 41aaa4055291a |
12 | 157b684574151 |
13 | 7427b73c1322 |
14 | 335301329309 |
15 | 17b5cd3cd011 |
hex | befb75b8ecd |
13124201320141 has 2 divisors, whose sum is σ = 13124201320142. Its totient is φ = 13124201320140.
The previous prime is 13124201320091. The next prime is 13124201320189. The reversal of 13124201320141 is 14102310242131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11799595982916 + 1324605337225 = 3435054^2 + 1150915^2 .
It is a cyclic number.
It is not a de Polignac number, because 13124201320141 - 221 = 13124199222989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124201320441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562100660070 + 6562100660071.
It is an arithmetic number, because the mean of its divisors is an integer number (6562100660071).
Almost surely, 213124201320141 is an apocalyptic number.
It is an amenable number.
13124201320141 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124201320141 is an equidigital number, since it uses as much as digits as its factorization.
13124201320141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13124201320141 its reverse (14102310242131), we get a palindrome (27226511562272).
The spelling of 13124201320141 in words is "thirteen trillion, one hundred twenty-four billion, two hundred one million, three hundred twenty thousand, one hundred forty-one".
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