Base | Representation |
---|---|
bin | 1011111011111011011101… |
… | …0110111000111100100111 |
3 | 1201110122212011012022122221 |
4 | 2332332313112320330213 |
5 | 3210011331014221411 |
6 | 43525101433533211 |
7 | 2523122641404001 |
oct | 276766726707447 |
9 | 51418764168587 |
10 | 13124201320231 |
11 | 41aaa405529a1 |
12 | 157b684574207 |
13 | 7427b73c1391 |
14 | 335301329371 |
15 | 17b5cd3cd071 |
hex | befb75b8f27 |
13124201320231 has 2 divisors, whose sum is σ = 13124201320232. Its totient is φ = 13124201320230.
The previous prime is 13124201320189. The next prime is 13124201320297. The reversal of 13124201320231 is 13202310242131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13124201320231 - 211 = 13124201318183 is a prime.
It is a super-2 number, since 2×131242013202312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13124201320196 and 13124201320205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124201320831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562100660115 + 6562100660116.
It is an arithmetic number, because the mean of its divisors is an integer number (6562100660116).
Almost surely, 213124201320231 is an apocalyptic number.
13124201320231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124201320231 is an equidigital number, since it uses as much as digits as its factorization.
13124201320231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13124201320231 its reverse (13202310242131), we get a palindrome (26326511562362).
The spelling of 13124201320231 in words is "thirteen trillion, one hundred twenty-four billion, two hundred one million, three hundred twenty thousand, two hundred thirty-one".
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