Base | Representation |
---|---|
bin | 1011111011111011011110… |
… | …0001001101000100110010 |
3 | 1201110122212100021200200202 |
4 | 2332332313201031010302 |
5 | 3210011332212232424 |
6 | 43525102011515202 |
7 | 2523123003365021 |
oct | 276766741150462 |
9 | 51418770250622 |
10 | 13124204024114 |
11 | 41aaa4202a407 |
12 | 157b685458b02 |
13 | 7427b7b2a001 |
14 | 3353018308b8 |
15 | 17b5cd7642ae |
hex | befb784d132 |
13124204024114 has 8 divisors (see below), whose sum is σ = 19686412326528. Its totient is φ = 6562066581940.
The previous prime is 13124204024111. The next prime is 13124204024147. The reversal of 13124204024114 is 41142040242131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×131242040241142 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13124204024111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17249582 + ... + 17994345.
It is an arithmetic number, because the mean of its divisors is an integer number (2460801540816).
Almost surely, 213124204024114 is an apocalyptic number.
13124204024114 is a deficient number, since it is larger than the sum of its proper divisors (6562208302414).
13124204024114 is a wasteful number, since it uses less digits than its factorization.
13124204024114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35430120.
The product of its (nonzero) digits is 6144, while the sum is 29.
Adding to 13124204024114 its reverse (41142040242131), we get a palindrome (54266244266245).
The spelling of 13124204024114 in words is "thirteen trillion, one hundred twenty-four billion, two hundred four million, twenty-four thousand, one hundred fourteen".
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