13124204024113 has 32 divisors (see below), whose sum is σ = 16555021056000. Its totient is φ = 10188060712128.

The previous prime is 13124204024111. The next prime is 13124204024147. The reversal of 13124204024113 is 31142040242131.

It is a happy number.

It is not a de Polignac number, because 13124204024113 - 2¹ = 13124204024111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13124204024111) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7235713 + ... + 8865886.

It is an arithmetic number, because the mean of its divisors is an integer number (517344408000).

Almost surely, 2^{13124204024113} is an apocalyptic number.

13124204024113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13124204024113 is a deficient number, since it is larger than the sum of its proper divisors (3430817031887).

13124204024113 is an equidigital number, since it uses as much as digits as its factorization.

13124204024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16101698 (or 16101672 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 13124204024113 its reverse (31142040242131), we get a palindrome (44266244266244).

The spelling of 13124204024113 in words is "thirteen trillion, one hundred twenty-four billion, two hundred four million, twenty-four thousand, one hundred thirteen".