Base | Representation |
---|---|
bin | 11101110101110100110001… |
… | …010100100000001001010011 |
3 | 122012200121220121102210221202 |
4 | 131311310301110200021103 |
5 | 114200232402114401003 |
6 | 1143043450323541415 |
7 | 36433634440062434 |
oct | 3565646124401123 |
9 | 565617817383852 |
10 | 131242143122003 |
11 | 388aa531353671 |
12 | 1287773422a86b |
13 | 5830108c2ab74 |
14 | 245a22176748b |
15 | 1028d98ea0088 |
hex | 775d31520253 |
131242143122003 has 2 divisors, whose sum is σ = 131242143122004. Its totient is φ = 131242143122002.
The previous prime is 131242143121927. The next prime is 131242143122009. The reversal of 131242143122003 is 300221341242131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131242143122003 - 212 = 131242143117907 is a prime.
It is not a weakly prime, because it can be changed into another prime (131242143122009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621071561001 + 65621071561002.
It is an arithmetic number, because the mean of its divisors is an integer number (65621071561002).
Almost surely, 2131242143122003 is an apocalyptic number.
131242143122003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131242143122003 is an equidigital number, since it uses as much as digits as its factorization.
131242143122003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 131242143122003 its reverse (300221341242131), we get a palindrome (431463484364134).
The spelling of 131242143122003 in words is "one hundred thirty-one trillion, two hundred forty-two billion, one hundred forty-three million, one hundred twenty-two thousand, three".
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