Base | Representation |
---|---|
bin | 11101110101110100110001… |
… | …110000101111001000100111 |
3 | 122012200121221010100211210201 |
4 | 131311310301300233020213 |
5 | 114200232411013222211 |
6 | 1143043451150331331 |
7 | 36433634560020103 |
oct | 3565646160571047 |
9 | 565617833324721 |
10 | 131242150523431 |
11 | 388aa535549452 |
12 | 128777367b9b47 |
13 | 583010a61c9cc |
14 | 245a222732903 |
15 | 1028d999630c1 |
hex | 775d31c2f227 |
131242150523431 has 2 divisors, whose sum is σ = 131242150523432. Its totient is φ = 131242150523430.
The previous prime is 131242150523423. The next prime is 131242150523461. The reversal of 131242150523431 is 134325051242131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131242150523431 - 23 = 131242150523423 is a prime.
It is a super-2 number, since 2×1312421505234312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131242150523401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621075261715 + 65621075261716.
It is an arithmetic number, because the mean of its divisors is an integer number (65621075261716).
Almost surely, 2131242150523431 is an apocalyptic number.
131242150523431 is a deficient number, since it is larger than the sum of its proper divisors (1).
131242150523431 is an equidigital number, since it uses as much as digits as its factorization.
131242150523431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 131242150523431 in words is "one hundred thirty-one trillion, two hundred forty-two billion, one hundred fifty million, five hundred twenty-three thousand, four hundred thirty-one".
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