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131242150523431 is a prime number
BaseRepresentation
bin11101110101110100110001…
…110000101111001000100111
3122012200121221010100211210201
4131311310301300233020213
5114200232411013222211
61143043451150331331
736433634560020103
oct3565646160571047
9565617833324721
10131242150523431
11388aa535549452
12128777367b9b47
13583010a61c9cc
14245a222732903
151028d999630c1
hex775d31c2f227

131242150523431 has 2 divisors, whose sum is σ = 131242150523432. Its totient is φ = 131242150523430.

The previous prime is 131242150523423. The next prime is 131242150523461. The reversal of 131242150523431 is 134325051242131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131242150523431 - 23 = 131242150523423 is a prime.

It is a super-2 number, since 2×1312421505234312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131242150523401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621075261715 + 65621075261716.

It is an arithmetic number, because the mean of its divisors is an integer number (65621075261716).

Almost surely, 2131242150523431 is an apocalyptic number.

131242150523431 is a deficient number, since it is larger than the sum of its proper divisors (1).

131242150523431 is an equidigital number, since it uses as much as digits as its factorization.

131242150523431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

The spelling of 131242150523431 in words is "one hundred thirty-one trillion, two hundred forty-two billion, one hundred fifty million, five hundred twenty-three thousand, four hundred thirty-one".