Base | Representation |
---|---|
bin | 1011111011111011100111… |
… | …0010000100110001101001 |
3 | 1201110122221222202010012010 |
4 | 2332332321302010301221 |
5 | 3210011421423013001 |
6 | 43525105445510133 |
7 | 2523123644235555 |
oct | 276767162046151 |
9 | 51418858663163 |
10 | 13124242001001 |
11 | 41aaa61508a6a |
12 | 157b696112349 |
13 | 7427c2965a41 |
14 | 3353068b8865 |
15 | 17b5d1c668d6 |
hex | befb9c84c69 |
13124242001001 has 8 divisors (see below), whose sum is σ = 18528341648544. Its totient is φ = 8234818510400.
The previous prime is 13124242000997. The next prime is 13124242001011. The reversal of 13124242001001 is 10010024242131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13124242001001 - 22 = 13124242000997 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13124242001011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128669039175 + ... + 128669039276.
It is an arithmetic number, because the mean of its divisors is an integer number (2316042706068).
Almost surely, 213124242001001 is an apocalyptic number.
It is an amenable number.
13124242001001 is a deficient number, since it is larger than the sum of its proper divisors (5404099647543).
13124242001001 is a wasteful number, since it uses less digits than its factorization.
13124242001001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 257338078471.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 13124242001001 its reverse (10010024242131), we get a palindrome (23134266243132).
The spelling of 13124242001001 in words is "thirteen trillion, one hundred twenty-four billion, two hundred forty-two million, one thousand, one".
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