Base | Representation |
---|---|
bin | 11000011100100010… |
… | …10010000101011010 |
3 | 1020212122201012102202 |
4 | 30032101102011122 |
5 | 203334311012214 |
6 | 10010151330202 |
7 | 643142552321 |
oct | 141621220532 |
9 | 36778635382 |
10 | 13124313434 |
11 | 5625372a31 |
12 | 2663380962 |
13 | 131207904b |
14 | 8c70890b8 |
15 | 51c30a6de |
hex | 30e45215a |
13124313434 has 4 divisors (see below), whose sum is σ = 19686470154. Its totient is φ = 6562156716.
The previous prime is 13124313353. The next prime is 13124313443. The reversal of 13124313434 is 43431342131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6798497209 + 6325816225 = 82453^2 + 79535^2 .
It is a super-2 number, since 2×131243134342 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13124313397 and 13124313406.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281078357 + ... + 3281078360.
Almost surely, 213124313434 is an apocalyptic number.
13124313434 is a deficient number, since it is larger than the sum of its proper divisors (6562156720).
13124313434 is an equidigital number, since it uses as much as digits as its factorization.
13124313434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6562156719.
The product of its digits is 10368, while the sum is 29.
Adding to 13124313434 its reverse (43431342131), we get a palindrome (56555655565).
The spelling of 13124313434 in words is "thirteen billion, one hundred twenty-four million, three hundred thirteen thousand, four hundred thirty-four".
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