Base | Representation |
---|---|
bin | 111101000111010110… |
… | …1001111101001100101 |
3 | 110112202120022120221211 |
4 | 1322032231033221211 |
5 | 4122241232303013 |
6 | 140143050111421 |
7 | 12324221111551 |
oct | 1721655175145 |
9 | 415676276854 |
10 | 131243244133 |
11 | 50729431921 |
12 | 2152911b571 |
13 | c4b762a351 |
14 | 64d0654861 |
15 | 363209223d |
hex | 1e8eb4fa65 |
131243244133 has 2 divisors, whose sum is σ = 131243244134. Its totient is φ = 131243244132.
The previous prime is 131243244109. The next prime is 131243244149. The reversal of 131243244133 is 331442342131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125190715329 + 6052528804 = 353823^2 + 77798^2 .
It is a cyclic number.
It is not a de Polignac number, because 131243244133 - 229 = 130706373221 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131243244095 and 131243244104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131243244163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621622066 + 65621622067.
It is an arithmetic number, because the mean of its divisors is an integer number (65621622067).
Almost surely, 2131243244133 is an apocalyptic number.
It is an amenable number.
131243244133 is a deficient number, since it is larger than the sum of its proper divisors (1).
131243244133 is an equidigital number, since it uses as much as digits as its factorization.
131243244133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 31.
Adding to 131243244133 its reverse (331442342131), we get a palindrome (462685586264).
The spelling of 131243244133 in words is "one hundred thirty-one billion, two hundred forty-three million, two hundred forty-four thousand, one hundred thirty-three".
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