13124331142513 has 4 divisors (see below), whose sum is σ = 13125108529008. Its totient is φ = 13123553756020.

The previous prime is 13124331142511. The next prime is 13124331142567. The reversal of 13124331142513 is 31524113342131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124331142513 - 2¹ = 13124331142511 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124331142511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388667923 + ... + 388701688.

It is an arithmetic number, because the mean of its divisors is an integer number (3281277132252).

Almost surely, 2^{13124331142513} is an apocalyptic number.

It is an amenable number.

13124331142513 is a deficient number, since it is larger than the sum of its proper divisors (777386495).

13124331142513 is an equidigital number, since it uses as much as digits as its factorization.

13124331142513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 777386494.

The product of its digits is 25920, while the sum is 34.

Adding to 13124331142513 its reverse (31524113342131), we get a palindrome (44648444484644).

The spelling of 13124331142513 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-one million, one hundred forty-two thousand, five hundred thirteen".