13124331142514 has 4 divisors (see below), whose sum is σ = 19686496713774. Its totient is φ = 6562165571256.

The previous prime is 13124331142511. The next prime is 13124331142567. The reversal of 13124331142514 is 41524113342131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12259276755625 + 865054386889 = 3501325^2 + 930083^2 .

It is not an unprimeable number, because it can be changed into a prime (13124331142511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281082785627 + ... + 3281082785630.

Almost surely, 2^{13124331142514} is an apocalyptic number.

13124331142514 is a deficient number, since it is larger than the sum of its proper divisors (6562165571260).

13124331142514 is an equidigital number, since it uses as much as digits as its factorization.

13124331142514 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6562165571259.

The product of its digits is 34560, while the sum is 35.

Adding to 13124331142514 its reverse (41524113342131), we get a palindrome (54648444484645).

The spelling of 13124331142514 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-one million, one hundred forty-two thousand, five hundred fourteen".