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13124333400133 is a prime number
BaseRepresentation
bin1011111011111011111100…
…1110101111000001000101
31201110200012100201200020011
42332332333032233001011
53210012113322301013
643525122512510221
72523126134146414
oct276767716570105
951420170650204
1013124333400133
1141aaaa906553a
12157b70084b371
13742808887777
14335314aab47b
1517b5d9cbcc3d
hexbefbf3af045

13124333400133 has 2 divisors, whose sum is σ = 13124333400134. Its totient is φ = 13124333400132.

The previous prime is 13124333400121. The next prime is 13124333400137. The reversal of 13124333400133 is 33100433342131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9205386585444 + 3918946814689 = 3034038^2 + 1979633^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124333400133 - 29 = 13124333399621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124333400095 and 13124333400104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124333400137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562166700066 + 6562166700067.

It is an arithmetic number, because the mean of its divisors is an integer number (6562166700067).

Almost surely, 213124333400133 is an apocalyptic number.

It is an amenable number.

13124333400133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124333400133 is an equidigital number, since it uses as much as digits as its factorization.

13124333400133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13124333400133 its reverse (33100433342131), we get a palindrome (46224766742264).

The spelling of 13124333400133 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-three million, four hundred thousand, one hundred thirty-three".