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13124341543043 is a prime number
BaseRepresentation
bin1011111011111011111110…
…1101110011000010000011
31201110200012221001101012102
42332332333231303002003
53210012122413334133
643525123403221015
72523126263312603
oct276767755630203
951420187041172
1013124341543043
114200002717415
12157b70351776b
1374280a478c63
14335315bcac03
1517b5da87a7e8
hexbefbfb73083

13124341543043 has 2 divisors, whose sum is σ = 13124341543044. Its totient is φ = 13124341543042.

The previous prime is 13124341542967. The next prime is 13124341543081. The reversal of 13124341543043 is 34034514342131.

It is an a-pointer prime, because the next prime (13124341543081) can be obtained adding 13124341543043 to its sum of digits (38).

It is a strong prime.

It is an emirp because it is prime and its reverse (34034514342131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13124341543043 - 220 = 13124340494467 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124341542988 and 13124341543006.

It is not a weakly prime, because it can be changed into another prime (13124341542043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562170771521 + 6562170771522.

It is an arithmetic number, because the mean of its divisors is an integer number (6562170771522).

Almost surely, 213124341543043 is an apocalyptic number.

13124341543043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124341543043 is an equidigital number, since it uses as much as digits as its factorization.

13124341543043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 38.

Adding to 13124341543043 its reverse (34034514342131), we get a palindrome (47158855885174).

The spelling of 13124341543043 in words is "thirteen trillion, one hundred twenty-four billion, three hundred forty-one million, five hundred forty-three thousand, forty-three".