Base | Representation |
---|---|
bin | 11101110101110101111110… |
… | …101100010111100111110111 |
3 | 122012200202021002001020101021 |
4 | 131311311332230113213313 |
5 | 114200243031423133213 |
6 | 1143044223214442011 |
7 | 36434011551550051 |
oct | 3565657654274767 |
9 | 565622232036337 |
10 | 131243441224183 |
11 | 38900038074a92 |
12 | 12877a36b03307 |
13 | 5830284b50072 |
14 | 245a305d128d1 |
15 | 1028e22e17d8d |
hex | 775d7eb179f7 |
131243441224183 has 2 divisors, whose sum is σ = 131243441224184. Its totient is φ = 131243441224182.
The previous prime is 131243441224153. The next prime is 131243441224249. The reversal of 131243441224183 is 381422144342131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131243441224183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131243441224153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65621720612091 + 65621720612092.
It is an arithmetic number, because the mean of its divisors is an integer number (65621720612092).
Almost surely, 2131243441224183 is an apocalyptic number.
131243441224183 is a deficient number, since it is larger than the sum of its proper divisors (1).
131243441224183 is an equidigital number, since it uses as much as digits as its factorization.
131243441224183 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 442368, while the sum is 43.
The spelling of 131243441224183 in words is "one hundred thirty-one trillion, two hundred forty-three billion, four hundred forty-one million, two hundred twenty-four thousand, one hundred eighty-three".
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