Base | Representation |
---|---|
bin | 1011111011111011111111… |
… | …0111111100010001101111 |
3 | 1201110200020010001111002022 |
4 | 2332332333313330101233 |
5 | 3210012124103433401 |
6 | 43525123540220355 |
7 | 2523126325026644 |
oct | 276767767742157 |
9 | 51420203044068 |
10 | 13124344202351 |
11 | 4200004173398 |
12 | 157b70439a6bb |
13 | 74280ab9a505 |
14 | 3353162bddcb |
15 | 17b5dac0371b |
hex | befbfdfc46f |
13124344202351 has 2 divisors, whose sum is σ = 13124344202352. Its totient is φ = 13124344202350.
The previous prime is 13124344202293. The next prime is 13124344202363. The reversal of 13124344202351 is 15320244342131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13124344202351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124344702351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562172101175 + 6562172101176.
It is an arithmetic number, because the mean of its divisors is an integer number (6562172101176).
Almost surely, 213124344202351 is an apocalyptic number.
13124344202351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124344202351 is an equidigital number, since it uses as much as digits as its factorization.
13124344202351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 13124344202351 its reverse (15320244342131), we get a palindrome (28444588544482).
The spelling of 13124344202351 in words is "thirteen trillion, one hundred twenty-four billion, three hundred forty-four million, two hundred two thousand, three hundred fifty-one".
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