Base | Representation |
---|---|
bin | 1011111011111100001101… |
… | …1101001111010010101011 |
3 | 1201110200101022011022221101 |
4 | 2332333003131033102223 |
5 | 3210012240000424321 |
6 | 43525133524422231 |
7 | 2523130654656304 |
oct | 276770335172253 |
9 | 51420338138841 |
10 | 13124404311211 |
11 | 4200035099036 |
12 | 157b720547977 |
13 | 74281a484b9b |
14 | 3353202897ab |
15 | 17b5e1128791 |
hex | befc374f4ab |
13124404311211 has 2 divisors, whose sum is σ = 13124404311212. Its totient is φ = 13124404311210.
The previous prime is 13124404311199. The next prime is 13124404311229. The reversal of 13124404311211 is 11211340442131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13124404311211 - 227 = 13124270093483 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13124404311211.
It is not a weakly prime, because it can be changed into another prime (13124404311251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562202155605 + 6562202155606.
It is an arithmetic number, because the mean of its divisors is an integer number (6562202155606).
Almost surely, 213124404311211 is an apocalyptic number.
13124404311211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124404311211 is an equidigital number, since it uses as much as digits as its factorization.
13124404311211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 13124404311211 its reverse (11211340442131), we get a palindrome (24335744753342).
The spelling of 13124404311211 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, three hundred eleven thousand, two hundred eleven".
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