Base | Representation |
---|---|
bin | 1011111011111100001101… |
… | …1101001111010010011111 |
3 | 1201110200101022011022220221 |
4 | 2332333003131033102133 |
5 | 3210012240000424244 |
6 | 43525133524422211 |
7 | 2523130654656256 |
oct | 276770335172237 |
9 | 51420338138827 |
10 | 13124404311199 |
11 | 4200035099025 |
12 | 157b720547967 |
13 | 74281a484b8c |
14 | 33532028979d |
15 | 17b5e1128784 |
hex | befc374f49f |
13124404311199 has 2 divisors, whose sum is σ = 13124404311200. Its totient is φ = 13124404311198.
The previous prime is 13124404311197. The next prime is 13124404311211. The reversal of 13124404311199 is 99111340442131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13124404311199 - 21 = 13124404311197 is a prime.
Together with 13124404311197, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13124404311197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562202155599 + 6562202155600.
It is an arithmetic number, because the mean of its divisors is an integer number (6562202155600).
Almost surely, 213124404311199 is an apocalyptic number.
13124404311199 is a deficient number, since it is larger than the sum of its proper divisors (1).
13124404311199 is an equidigital number, since it uses as much as digits as its factorization.
13124404311199 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 43.
The spelling of 13124404311199 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, three hundred eleven thousand, one hundred ninety-nine".
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