13124404535147 has 2 divisors, whose sum is σ = 13124404535148. Its totient is φ = 13124404535146.

The previous prime is 13124404535083. The next prime is 13124404535159. The reversal of 13124404535147 is 74153540442131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13124404535147 - 2⁶ = 13124404535083 is a prime.

It is a super-3 number, since 3×13124404535147³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13124404535098 and 13124404535107.

It is not a weakly prime, because it can be changed into another prime (13124404525147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562202267573 + 6562202267574.

It is an arithmetic number, because the mean of its divisors is an integer number (6562202267574).

Almost surely, 2^{13124404535147} is an apocalyptic number.

13124404535147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124404535147 is an equidigital number, since it uses as much as digits as its factorization.

13124404535147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 806400, while the sum is 44.

Adding to 13124404535147 its reverse (74153540442131), we get a palindrome (87277944977278).

The spelling of 13124404535147 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, five hundred thirty-five thousand, one hundred forty-seven".