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13124412445093 is a prime number
BaseRepresentation
bin1011111011111100001111…
…1100010001000110100101
31201110200101212110120112021
42332333003330101012211
53210012244041220333
643525134415023141
72523131114054245
oct276770374210645
951420355416467
1013124412445093
114200039744154
12157b72320aab1
1374281c072231
143353213a5b25
1517b5e1bd382d
hexbefc3f111a5

13124412445093 has 2 divisors, whose sum is σ = 13124412445094. Its totient is φ = 13124412445092.

The previous prime is 13124412445087. The next prime is 13124412445147. The reversal of 13124412445093 is 39054421442131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12790937379364 + 333475065729 = 3576442^2 + 577473^2 .

It is an emirp because it is prime and its reverse (39054421442131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124412445093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124412445393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562206222546 + 6562206222547.

It is an arithmetic number, because the mean of its divisors is an integer number (6562206222547).

Almost surely, 213124412445093 is an apocalyptic number.

It is an amenable number.

13124412445093 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124412445093 is an equidigital number, since it uses as much as digits as its factorization.

13124412445093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 43.

The spelling of 13124412445093 in words is "thirteen trillion, one hundred twenty-four billion, four hundred twelve million, four hundred forty-five thousand, ninety-three".