13124412501493 has 2 divisors, whose sum is σ = 13124412501494. Its totient is φ = 13124412501492.

The previous prime is 13124412501461. The next prime is 13124412501517. The reversal of 13124412501493 is 39410521442131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8221168438564 + 4903244062929 = 2867258^2 + 2214327^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124412501493 - 2⁵ = 13124412501461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13124412501793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562206250746 + 6562206250747.

It is an arithmetic number, because the mean of its divisors is an integer number (6562206250747).

Almost surely, 2^{13124412501493} is an apocalyptic number.

It is an amenable number.

13124412501493 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124412501493 is an equidigital number, since it uses as much as digits as its factorization.

13124412501493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 40.

The spelling of 13124412501493 in words is "thirteen trillion, one hundred twenty-four billion, four hundred twelve million, five hundred one thousand, four hundred ninety-three".