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13124414013443 = 13669960159047
BaseRepresentation
bin1011111011111100010000…
…0010010000000000000011
31201110200101222102020220022
42332333010002100000003
53210012244441412233
643525134512404055
72523131133305555
oct276770402200003
951420358366808
1013124414013443
11420003a615507
12157b72384662b
1374281c4a1055
143353216934d5
1517b5e1de3398
hexbefc4090003

13124414013443 has 4 divisors (see below), whose sum is σ = 13125374186160. Its totient is φ = 13123453840728.

The previous prime is 13124414013413. The next prime is 13124414013481. The reversal of 13124414013443 is 34431041442131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13124414013443 - 26 = 13124414013379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124414013413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 480065855 + ... + 480093192.

It is an arithmetic number, because the mean of its divisors is an integer number (3281343546540).

Almost surely, 213124414013443 is an apocalyptic number.

13124414013443 is a deficient number, since it is larger than the sum of its proper divisors (960172717).

13124414013443 is an equidigital number, since it uses as much as digits as its factorization.

13124414013443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 960172716.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 13124414013443 its reverse (34431041442131), we get a palindrome (47555455455574).

The spelling of 13124414013443 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fourteen million, thirteen thousand, four hundred forty-three".

Divisors: 1 13669 960159047 13124414013443