Base | Representation |
---|---|
bin | 1011111011111100010000… |
… | …0010010000000000000011 |
3 | 1201110200101222102020220022 |
4 | 2332333010002100000003 |
5 | 3210012244441412233 |
6 | 43525134512404055 |
7 | 2523131133305555 |
oct | 276770402200003 |
9 | 51420358366808 |
10 | 13124414013443 |
11 | 420003a615507 |
12 | 157b72384662b |
13 | 74281c4a1055 |
14 | 3353216934d5 |
15 | 17b5e1de3398 |
hex | befc4090003 |
13124414013443 has 4 divisors (see below), whose sum is σ = 13125374186160. Its totient is φ = 13123453840728.
The previous prime is 13124414013413. The next prime is 13124414013481. The reversal of 13124414013443 is 34431041442131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13124414013443 - 26 = 13124414013379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13124414013413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 480065855 + ... + 480093192.
It is an arithmetic number, because the mean of its divisors is an integer number (3281343546540).
Almost surely, 213124414013443 is an apocalyptic number.
13124414013443 is a deficient number, since it is larger than the sum of its proper divisors (960172717).
13124414013443 is an equidigital number, since it uses as much as digits as its factorization.
13124414013443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 960172716.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 13124414013443 its reverse (34431041442131), we get a palindrome (47555455455574).
The spelling of 13124414013443 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fourteen million, thirteen thousand, four hundred forty-three".
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