13124414341441 has 4 divisors (see below), whose sum is σ = 14133984675412. Its totient is φ = 12114844007472.

The previous prime is 13124414341433. The next prime is 13124414341447. The reversal of 13124414341441 is 14414341442131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3129148723600 + 9995265617841 = 1768940^2 + 3161529^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124414341441 - 2³ = 13124414341433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13124414341441.

It is not an unprimeable number, because it can be changed into a prime (13124414341447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504785166966 + ... + 504785166991.

It is an arithmetic number, because the mean of its divisors is an integer number (3533496168853).

Almost surely, 2^{13124414341441} is an apocalyptic number.

It is an amenable number.

13124414341441 is a deficient number, since it is larger than the sum of its proper divisors (1009570333971).

13124414341441 is a wasteful number, since it uses less digits than its factorization.

13124414341441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1009570333970.

The product of its digits is 73728, while the sum is 37.

Adding to 13124414341441 its reverse (14414341442131), we get a palindrome (27538755783572).

The spelling of 13124414341441 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fourteen million, three hundred forty-one thousand, four hundred forty-one".