13124431112044 has 192 divisors, whose sum is σ = 28216434032640. Its totient is φ = 5213891773440.

The previous prime is 13124431111997. The next prime is 13124431112053. The reversal of 13124431112044 is 44021113442131.

It is a junction number, because it is equal to n+sod(n) for n = 13124431111997 and 13124431112015.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8922114229 + ... + 8922115699.

It is an arithmetic number, because the mean of its divisors is an integer number (146960593920).

Almost surely, 2^{13124431112044} is an apocalyptic number.

13124431112044 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13124431112044, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14108217016320).

13124431112044 is an abundant number, since it is smaller than the sum of its proper divisors (15092002920596).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13124431112044 is a wasteful number, since it uses less digits than its factorization.

13124431112044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2508 (or 2506 counting only the distinct ones).

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13124431112044 its reverse (44021113442131), we get a palindrome (57145544554175).

The spelling of 13124431112044 in words is "thirteen trillion, one hundred twenty-four billion, four hundred thirty-one million, one hundred twelve thousand, forty-four".