Base | Representation |
---|---|
bin | 111101000111011000… |
… | …1111010100101100101 |
3 | 110112202122121210120202 |
4 | 1322032301322211211 |
5 | 4122242040443311 |
6 | 140143132240245 |
7 | 12324234401432 |
oct | 1721661724545 |
9 | 415678553522 |
10 | 131244468581 |
11 | 5072a098866 |
12 | 21529610085 |
13 | c4b7968785 |
14 | 64d0892b89 |
15 | 3632234e3b |
hex | 1e8ec7a965 |
131244468581 has 2 divisors, whose sum is σ = 131244468582. Its totient is φ = 131244468580.
The previous prime is 131244468557. The next prime is 131244468587. The reversal of 131244468581 is 185864442131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130805188900 + 439279681 = 361670^2 + 20959^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131244468581 is a prime.
It is a super-2 number, since 2×1312444685812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131244468587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65622234290 + 65622234291.
It is an arithmetic number, because the mean of its divisors is an integer number (65622234291).
Almost surely, 2131244468581 is an apocalyptic number.
It is an amenable number.
131244468581 is a deficient number, since it is larger than the sum of its proper divisors (1).
131244468581 is an equidigital number, since it uses as much as digits as its factorization.
131244468581 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 737280, while the sum is 47.
The spelling of 131244468581 in words is "one hundred thirty-one billion, two hundred forty-four million, four hundred sixty-eight thousand, five hundred eighty-one".
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