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13124504153 is a prime number
BaseRepresentation
bin11000011100100100…
…00000101001011001
31020212200001220001102
430032102000221121
5203334333113103
610010155401145
7643144305335
oct141622005131
936780056042
1013124504153
115625493252
1226634531b5
131312114ab7
148c70d87c5
1551c346e88
hex30e480a59

13124504153 has 2 divisors, whose sum is σ = 13124504154. Its totient is φ = 13124504152.

The previous prime is 13124504117. The next prime is 13124504167. The reversal of 13124504153 is 35140542131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6790254409 + 6334249744 = 82403^2 + 79588^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13124504153 is a prime.

It is a super-2 number, since 2×131245041532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13124504753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562252076 + 6562252077.

It is an arithmetic number, because the mean of its divisors is an integer number (6562252077).

Almost surely, 213124504153 is an apocalyptic number.

It is an amenable number.

13124504153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124504153 is an equidigital number, since it uses as much as digits as its factorization.

13124504153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

The spelling of 13124504153 in words is "thirteen billion, one hundred twenty-four million, five hundred four thousand, one hundred fifty-three".