13124641333 has 2 divisors, whose sum is σ = 13124641334. Its totient is φ = 13124641332.

The previous prime is 13124641307. The next prime is 13124641351. The reversal of 13124641333 is 33314642131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11384249809 + 1740391524 = 106697^2 + 41718^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124641333 - 2⁹ = 13124640821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13124641295 and 13124641304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121641333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562320666 + 6562320667.

It is an arithmetic number, because the mean of its divisors is an integer number (6562320667).

Almost surely, 2^13124641333 is an apocalyptic number.

It is an amenable number.

13124641333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13124641333 is an equidigital number, since it uses as much as digits as its factorization.

13124641333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15552, while the sum is 31.

The spelling of 13124641333 in words is "thirteen billion, one hundred twenty-four million, six hundred forty-one thousand, three hundred thirty-three".