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131252118229231 is a prime number
BaseRepresentation
bin11101110101111110000011…
…111000100001000011101111
3122012201120122210100202121121
4131311332003320201003233
5114200413314231313411
61143052220221041411
736434436563066626
oct3565760370410357
9565646583322547
10131252118229231
113890379000633a
12128796589b6267
135831038710b8c
14245a8ca48a6bd
15102927ea92571
hex775f83e210ef

131252118229231 has 2 divisors, whose sum is σ = 131252118229232. Its totient is φ = 131252118229230.

The previous prime is 131252118229163. The next prime is 131252118229249. The reversal of 131252118229231 is 132922811252131.

It is a strong prime.

It is an emirp because it is prime and its reverse (132922811252131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131252118229231 - 229 = 131251581358319 is a prime.

It is a super-2 number, since 2×1312521182292312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131252118229261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65626059114615 + 65626059114616.

It is an arithmetic number, because the mean of its divisors is an integer number (65626059114616).

Almost surely, 2131252118229231 is an apocalyptic number.

131252118229231 is a deficient number, since it is larger than the sum of its proper divisors (1).

131252118229231 is an equidigital number, since it uses as much as digits as its factorization.

131252118229231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 43.

The spelling of 131252118229231 in words is "one hundred thirty-one trillion, two hundred fifty-two billion, one hundred eighteen million, two hundred twenty-nine thousand, two hundred thirty-one".