13125253540451 has 16 divisors (see below), whose sum is σ = 14276680699680. Its totient is φ = 11994113395200.

The previous prime is 13125253540439. The next prime is 13125253540493. The reversal of 13125253540451 is 15404535252131.

It is a cyclic number.

It is not a de Polignac number, because 13125253540451 - 2²² = 13125249346147 is a prime.

It is a super-2 number, since 2×13125253540451² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13125253540399 and 13125253540408.

It is not an unprimeable number, because it can be changed into a prime (13125253540411) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9590840 + ... + 10873578.

It is an arithmetic number, because the mean of its divisors is an integer number (892292543730).

Almost surely, 2^{13125253540451} is an apocalyptic number.

13125253540451 is a deficient number, since it is larger than the sum of its proper divisors (1151427159229).

13125253540451 is a wasteful number, since it uses less digits than its factorization.

13125253540451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1290646.

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 13125253540451 its reverse (15404535252131), we get a palindrome (28529788792582).

The spelling of 13125253540451 in words is "thirteen trillion, one hundred twenty-five billion, two hundred fifty-three million, five hundred forty thousand, four hundred fifty-one".