Base | Representation |
---|---|
bin | 1011111011111111011000… |
… | …0111111001011001000101 |
3 | 1201110202120112200000010012 |
4 | 2332333312013321121011 |
5 | 3210021010103321001 |
6 | 43525354132040005 |
7 | 2523161016140522 |
oct | 276776607713105 |
9 | 51422515600105 |
10 | 13125254354501 |
11 | 42004309aa153 |
12 | 157b919163005 |
13 | 742924609a93 |
14 | 3353a1120149 |
15 | 17b640a882bb |
hex | beff61f9645 |
13125254354501 has 2 divisors, whose sum is σ = 13125254354502. Its totient is φ = 13125254354500.
The previous prime is 13125254354389. The next prime is 13125254354533. The reversal of 13125254354501 is 10545345252131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11621996901025 + 1503257453476 = 3409105^2 + 1226074^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13125254354501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13125254374501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562627177250 + 6562627177251.
It is an arithmetic number, because the mean of its divisors is an integer number (6562627177251).
Almost surely, 213125254354501 is an apocalyptic number.
It is an amenable number.
13125254354501 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125254354501 is an equidigital number, since it uses as much as digits as its factorization.
13125254354501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360000, while the sum is 41.
The spelling of 13125254354501 in words is "thirteen trillion, one hundred twenty-five billion, two hundred fifty-four million, three hundred fifty-four thousand, five hundred one".
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