Base | Representation |
---|---|
bin | 1011111011111111100011… |
… | …0110100110000000100011 |
3 | 1201110202200201211200011011 |
4 | 2332333320312212000203 |
5 | 3210021103314302212 |
6 | 43525402445401351 |
7 | 2523162113325142 |
oct | 276777066460043 |
9 | 51422621750134 |
10 | 13125300150307 |
11 | 4200454839224 |
12 | 157b930569257 |
13 | 742930c526a7 |
14 | 3353a7241759 |
15 | 17b644ad24a7 |
hex | beff8da6023 |
13125300150307 has 2 divisors, whose sum is σ = 13125300150308. Its totient is φ = 13125300150306.
The previous prime is 13125300150289. The next prime is 13125300150323. The reversal of 13125300150307 is 70305100352131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13125300150307 is a prime.
It is not a weakly prime, because it can be changed into another prime (13125301150307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562650075153 + 6562650075154.
It is an arithmetic number, because the mean of its divisors is an integer number (6562650075154).
Almost surely, 213125300150307 is an apocalyptic number.
13125300150307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125300150307 is an equidigital number, since it uses as much as digits as its factorization.
13125300150307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9450, while the sum is 31.
The spelling of 13125300150307 in words is "thirteen trillion, one hundred twenty-five billion, three hundred million, one hundred fifty thousand, three hundred seven".
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