Base | Representation |
---|---|
bin | 111101000111101001… |
… | …1110011011011000011 |
3 | 110112210021100010112010 |
4 | 1322033103303123003 |
5 | 4122301324232011 |
6 | 140144050504003 |
7 | 12324403041126 |
oct | 1721723633303 |
9 | 415707303463 |
10 | 131253352131 |
11 | 50734106140 |
12 | 21530595003 |
13 | c4b9759105 |
14 | 64d1b263bd |
15 | 3632ddc1a6 |
hex | 1e8f4f36c3 |
131253352131 has 48 divisors (see below), whose sum is σ = 197546307840. Its totient is φ = 76874097600.
The previous prime is 131253352103. The next prime is 131253352151.
131253352131 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 131253352131 - 215 = 131253319363 is a prime.
It is a super-2 number, since 2×1312533521312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131253352151) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 26604741 + ... + 26609673.
It is an arithmetic number, because the mean of its divisors is an integer number (4115548080).
Almost surely, 2131253352131 is an apocalyptic number.
131253352131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131253352131 is a deficient number, since it is larger than the sum of its proper divisors (66292955709).
131253352131 is a wasteful number, since it uses less digits than its factorization.
131253352131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5848 (or 5817 counting only the distinct ones).
The product of its digits is 8100, while the sum is 30.
It can be divided in two parts, 131253 and 352131, that added together give a palindrome (483384).
The spelling of 131253352131 in words is "one hundred thirty-one billion, two hundred fifty-three million, three hundred fifty-two thousand, one hundred thirty-one".
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