13125335343235 has 4 divisors (see below), whose sum is σ = 15750402411888. Its totient is φ = 10500268274584.

The previous prime is 13125335343233. The next prime is 13125335343271. The reversal of 13125335343235 is 53234353352131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13125335343235 - 2¹ = 13125335343233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13125335343191 and 13125335343200.

It is not an unprimeable number, because it can be changed into a prime (13125335343233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312533534319 + ... + 1312533534328.

It is an arithmetic number, because the mean of its divisors is an integer number (3937600602972).

Almost surely, 2^{13125335343235} is an apocalyptic number.

13125335343235 is a deficient number, since it is larger than the sum of its proper divisors (2625067068653).

13125335343235 is an equidigital number, since it uses as much as digits as its factorization.

13125335343235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2625067068652.

The product of its digits is 1458000, while the sum is 43.

Adding to 13125335343235 its reverse (53234353352131), we get a palindrome (66359688695366).

The spelling of 13125335343235 in words is "thirteen trillion, one hundred twenty-five billion, three hundred thirty-five million, three hundred forty-three thousand, two hundred thirty-five".