Base | Representation |
---|---|
bin | 100111000111011… |
… | …1011001111111111 |
3 | 10101110202201021211 |
4 | 1032032323033333 |
5 | 10142002114201 |
6 | 334124105251 |
7 | 44345240155 |
oct | 11616731777 |
9 | 3343681254 |
10 | 1312535551 |
11 | 61398a428 |
12 | 307695227 |
13 | 17bc06972 |
14 | c64653d5 |
15 | 7a369651 |
hex | 4e3bb3ff |
1312535551 has 2 divisors, whose sum is σ = 1312535552. Its totient is φ = 1312535550.
The previous prime is 1312535537. The next prime is 1312535557. The reversal of 1312535551 is 1555352131.
It is a strong prime.
It is an emirp because it is prime and its reverse (1555352131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312535551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312535557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656267775 + 656267776.
It is an arithmetic number, because the mean of its divisors is an integer number (656267776).
Almost surely, 21312535551 is an apocalyptic number.
1312535551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312535551 is an equidigital number, since it uses as much as digits as its factorization.
1312535551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11250, while the sum is 31.
The square root of 1312535551 is about 36228.9325125651. The cubic root of 1312535551 is about 1094.8896703611.
Adding to 1312535551 its reverse (1555352131), we get a palindrome (2867887682).
The spelling of 1312535551 in words is "one billion, three hundred twelve million, five hundred thirty-five thousand, five hundred fifty-one".
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