13125405244151 has 4 divisors (see below), whose sum is σ = 13125412680072. Its totient is φ = 13125397808232.

The previous prime is 13125405244121. The next prime is 13125405244181. The reversal of 13125405244151 is 15144250452131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is an interprime number because it is at equal distance from previous prime (13125405244121) and next prime (13125405244181).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13125405244151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125405244111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605945 + ... + 5159261.

It is an arithmetic number, because the mean of its divisors is an integer number (3281353170018).

Almost surely, 2^{13125405244151} is an apocalyptic number.

13125405244151 is a deficient number, since it is larger than the sum of its proper divisors (7435921).

13125405244151 is an equidigital number, since it uses as much as digits as its factorization.

13125405244151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7435920.

The product of its (nonzero) digits is 96000, while the sum is 38.

Adding to 13125405244151 its reverse (15144250452131), we get a palindrome (28269655696282).

The spelling of 13125405244151 in words is "thirteen trillion, one hundred twenty-five billion, four hundred five million, two hundred forty-four thousand, one hundred fifty-one".