Base | Representation |
---|---|
bin | 1011111011111111111101… |
… | …1110110000101111001110 |
3 | 1201110202222111001212021112 |
4 | 2332333333132300233032 |
5 | 3210021320300441220 |
6 | 43525421500532022 |
7 | 2523164633416040 |
oct | 276777736605716 |
9 | 51422874055245 |
10 | 13125411343310 |
11 | 4200501585172 |
12 | 157b961851012 |
13 | 74294acb4a76 |
14 | 3353b7d07a90 |
15 | 17b64e7485c5 |
hex | befff7b0bce |
13125411343310 has 16 divisors (see below), whose sum is σ = 27000846192096. Its totient is φ = 4500141031968.
The previous prime is 13125411343271. The next prime is 13125411343339. The reversal of 13125411343310 is 1334311452131.
It is a super-2 number, since 2×131254113433102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93752938097 + ... + 93752938236.
It is an arithmetic number, because the mean of its divisors is an integer number (1687552887006).
Almost surely, 213125411343310 is an apocalyptic number.
13125411343310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13125411343310 is an abundant number, since it is smaller than the sum of its proper divisors (13875434848786).
13125411343310 is a wasteful number, since it uses less digits than its factorization.
13125411343310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 187505876347.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 13125411343310 its reverse (1334311452131), we get a palindrome (14459722795441).
The spelling of 13125411343310 in words is "thirteen trillion, one hundred twenty-five billion, four hundred eleven million, three hundred forty-three thousand, three hundred ten".
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