Base | Representation |
---|---|
bin | 1011111011111111111110… |
… | …0101001101110011001011 |
3 | 1201110202222121020211010112 |
4 | 2332333333211031303023 |
5 | 3210021321214111321 |
6 | 43525422001104535 |
7 | 2523164653663511 |
oct | 276777745156313 |
9 | 51422877224115 |
10 | 13125413035211 |
11 | 4200502530334 |
12 | 157b96232814b |
13 | 74294b457ba9 |
14 | 3353b82284b1 |
15 | 17b64e97ea5b |
hex | befff94dccb |
13125413035211 has 2 divisors, whose sum is σ = 13125413035212. Its totient is φ = 13125413035210.
The previous prime is 13125413035183. The next prime is 13125413035219. The reversal of 13125413035211 is 11253031452131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13125413035211 - 210 = 13125413034187 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13125413035219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562706517605 + 6562706517606.
It is an arithmetic number, because the mean of its divisors is an integer number (6562706517606).
Almost surely, 213125413035211 is an apocalyptic number.
13125413035211 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125413035211 is an equidigital number, since it uses as much as digits as its factorization.
13125413035211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 13125413035211 its reverse (11253031452131), we get a palindrome (24378444487342).
The spelling of 13125413035211 in words is "thirteen trillion, one hundred twenty-five billion, four hundred thirteen million, thirty-five thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •