Base | Representation |
---|---|
bin | 1011111011111111111110… |
… | …0101001101110011010011 |
3 | 1201110202222121020211010211 |
4 | 2332333333211031303103 |
5 | 3210021321214111334 |
6 | 43525422001104551 |
7 | 2523164653663522 |
oct | 276777745156323 |
9 | 51422877224124 |
10 | 13125413035219 |
11 | 4200502530341 |
12 | 157b962328157 |
13 | 74294b457bb4 |
14 | 3353b82284b9 |
15 | 17b64e97ea64 |
hex | befff94dcd3 |
13125413035219 has 2 divisors, whose sum is σ = 13125413035220. Its totient is φ = 13125413035218.
The previous prime is 13125413035211. The next prime is 13125413035237. The reversal of 13125413035219 is 91253031452131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13125413035219 - 23 = 13125413035211 is a prime.
It is a super-2 number, since 2×131254130352192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13125413035211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562706517609 + 6562706517610.
It is an arithmetic number, because the mean of its divisors is an integer number (6562706517610).
Almost surely, 213125413035219 is an apocalyptic number.
13125413035219 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125413035219 is an equidigital number, since it uses as much as digits as its factorization.
13125413035219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 13125413035219 in words is "thirteen trillion, one hundred twenty-five billion, four hundred thirteen million, thirty-five thousand, two hundred nineteen".
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