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13125413035219 is a prime number
BaseRepresentation
bin1011111011111111111110…
…0101001101110011010011
31201110202222121020211010211
42332333333211031303103
53210021321214111334
643525422001104551
72523164653663522
oct276777745156323
951422877224124
1013125413035219
114200502530341
12157b962328157
1374294b457bb4
143353b82284b9
1517b64e97ea64
hexbefff94dcd3

13125413035219 has 2 divisors, whose sum is σ = 13125413035220. Its totient is φ = 13125413035218.

The previous prime is 13125413035211. The next prime is 13125413035237. The reversal of 13125413035219 is 91253031452131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13125413035219 - 23 = 13125413035211 is a prime.

It is a super-2 number, since 2×131254130352192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13125413035211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562706517609 + 6562706517610.

It is an arithmetic number, because the mean of its divisors is an integer number (6562706517610).

Almost surely, 213125413035219 is an apocalyptic number.

13125413035219 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125413035219 is an equidigital number, since it uses as much as digits as its factorization.

13125413035219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 40.

The spelling of 13125413035219 in words is "thirteen trillion, one hundred twenty-five billion, four hundred thirteen million, thirty-five thousand, two hundred nineteen".