Base | Representation |
---|---|
bin | 1011111011111111111110… |
… | …0110101111001101101100 |
3 | 1201110202222122000002110122 |
4 | 2332333333212233031230 |
5 | 3210021321314343340 |
6 | 43525422013424112 |
7 | 2523164660245013 |
oct | 276777746571554 |
9 | 51422878002418 |
10 | 13125413434220 |
11 | 420050278309a |
12 | 157b96249b038 |
13 | 74294b5676a9 |
14 | 3353b82cda7a |
15 | 17b64ea0cdb5 |
hex | befff9af36c |
13125413434220 has 48 divisors (see below), whose sum is σ = 29014750248960. Its totient is φ = 4973724575424.
The previous prime is 13125413434151. The next prime is 13125413434307. The reversal of 13125413434220 is 2243431452131.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16835477 + ... + 17597843.
It is an arithmetic number, because the mean of its divisors is an integer number (604473963520).
Almost surely, 213125413434220 is an apocalyptic number.
13125413434220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13125413434220 is an abundant number, since it is smaller than the sum of its proper divisors (15889336814740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13125413434220 is a wasteful number, since it uses less digits than its factorization.
13125413434220 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 807702 (or 807700 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 13125413434220 its reverse (2243431452131), we get a palindrome (15368844886351).
The spelling of 13125413434220 in words is "thirteen trillion, one hundred twenty-five billion, four hundred thirteen million, four hundred thirty-four thousand, two hundred twenty".
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