Base | Representation |
---|---|
bin | 1011111100000000000100… |
… | …1101101100001001100110 |
3 | 1201110210001111210020102122 |
4 | 2333000001031230021212 |
5 | 3210021400222010002 |
6 | 43525424420105542 |
7 | 2523165435531032 |
oct | 277000115541146 |
9 | 51423044706378 |
10 | 13125440422502 |
11 | 4200516a36861 |
12 | 157b96b5352b2 |
13 | 7429540268a5 |
14 | 3353bbb171c2 |
15 | 17b65208e6a2 |
hex | bf00136c266 |
13125440422502 has 4 divisors (see below), whose sum is σ = 19688160633756. Its totient is φ = 6562720211250.
The previous prime is 13125440422477. The next prime is 13125440422541. The reversal of 13125440422502 is 20522404452131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281360105624 + ... + 3281360105627.
It is an arithmetic number, because the mean of its divisors is an integer number (4922040158439).
Almost surely, 213125440422502 is an apocalyptic number.
13125440422502 is a deficient number, since it is larger than the sum of its proper divisors (6562720211254).
13125440422502 is an equidigital number, since it uses as much as digits as its factorization.
13125440422502 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6562720211253.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 13125440422502 its reverse (20522404452131), we get a palindrome (33647844874633).
The spelling of 13125440422502 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty million, four hundred twenty-two thousand, five hundred two".
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