Base | Representation |
---|---|
bin | 10011000110011010001… |
… | …100111101011111110011 |
3 | 11122110221000100220211022 |
4 | 103012122030331133303 |
5 | 133001101320123123 |
6 | 2442551135010055 |
7 | 163554156613403 |
oct | 23063214753763 |
9 | 4573830326738 |
10 | 1312552114163 |
11 | 4667174a5364 |
12 | 19246b06992b |
13 | 96a0875c824 |
14 | 47756646803 |
15 | 24220da51c8 |
hex | 1319a33d7f3 |
1312552114163 has 2 divisors, whose sum is σ = 1312552114164. Its totient is φ = 1312552114162.
The previous prime is 1312552114121. The next prime is 1312552114171. The reversal of 1312552114163 is 3614112552131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3614112552131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312552114163 - 26 = 1312552114099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312555114163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656276057081 + 656276057082.
It is an arithmetic number, because the mean of its divisors is an integer number (656276057082).
Almost surely, 21312552114163 is an apocalyptic number.
1312552114163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312552114163 is an equidigital number, since it uses as much as digits as its factorization.
1312552114163 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21600, while the sum is 35.
Adding to 1312552114163 its reverse (3614112552131), we get a palindrome (4926664666294).
The spelling of 1312552114163 in words is "one trillion, three hundred twelve billion, five hundred fifty-two million, one hundred fourteen thousand, one hundred sixty-three".
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