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131255505504023 = 2969171232581829
BaseRepresentation
bin11101110110000001001101…
…110001111100011100010111
3122012201220101212010011002112
4131312001031301330130113
5114200442233402112043
61143053540302101235
736434616533334425
oct3566011561743427
9565656355104075
10131255505504023
113890516903aa9a
121287a24327a81b
1358314583cc8a4
14245ab2c2a4115
1510293cc134518
hex77604dc7c717

131255505504023 has 8 divisors (see below), whose sum is σ = 131307433052400. Its totient is φ = 131203583159488.

The previous prime is 131255505503981. The next prime is 131255505504121. The reversal of 131255505504023 is 320405505552131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131255505504023 - 210 = 131255505502999 is a prime.

It is a super-2 number, since 2×1312555055040232 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131255505594023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49547273 + ... + 52129101.

It is an arithmetic number, because the mean of its divisors is an integer number (16413429131550).

Almost surely, 2131255505504023 is an apocalyptic number.

131255505504023 is a deficient number, since it is larger than the sum of its proper divisors (51927548377).

131255505504023 is a wasteful number, since it uses less digits than its factorization.

131255505504023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2601921.

The product of its (nonzero) digits is 450000, while the sum is 41.

The spelling of 131255505504023 in words is "one hundred thirty-one trillion, two hundred fifty-five billion, five hundred five million, five hundred four thousand, twenty-three".

Divisors: 1 2969 17123 2581829 50838187 7665450301 44208657967 131255505504023