Base | Representation |
---|---|
bin | 10011000110011011010… |
… | …001101010101101001100 |
3 | 11122110222021020222020020 |
4 | 103012123101222231030 |
5 | 133001120423001012 |
6 | 2442553021022140 |
7 | 163554465656460 |
oct | 23063321525514 |
9 | 4573867228206 |
10 | 1312570125132 |
11 | 466726687262 |
12 | 1924750b4950 |
13 | 96a0c3c77c6 |
14 | 47758bb44a0 |
15 | 24222761a8c |
hex | 1319b46ab4c |
1312570125132 has 24 divisors (see below), whose sum is σ = 3500187000576. Its totient is φ = 375020035728.
The previous prime is 1312570125101. The next prime is 1312570125157. The reversal of 1312570125132 is 2315210752131.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 1312570125093 and 1312570125102.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7812917328 + ... + 7812917495.
It is an arithmetic number, because the mean of its divisors is an integer number (145841125024).
Almost surely, 21312570125132 is an apocalyptic number.
1312570125132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1312570125132 is an abundant number, since it is smaller than the sum of its proper divisors (2187616875444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312570125132 is a wasteful number, since it uses less digits than its factorization.
1312570125132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15625834837 (or 15625834835 counting only the distinct ones).
The product of its (nonzero) digits is 12600, while the sum is 33.
Adding to 1312570125132 its reverse (2315210752131), we get a palindrome (3627780877263).
The spelling of 1312570125132 in words is "one trillion, three hundred twelve billion, five hundred seventy million, one hundred twenty-five thousand, one hundred thirty-two".
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