Base | Representation |
---|---|
bin | 11000011100110000… |
… | …10111010101111111 |
3 | 1020212210012112010211 |
4 | 30032120113111333 |
5 | 203340244414413 |
6 | 10010255213251 |
7 | 643164414103 |
oct | 141630272577 |
9 | 36783175124 |
10 | 13126169983 |
11 | 5626420873 |
12 | 2663b17227 |
13 | 13125790b4 |
14 | 8c740d903 |
15 | 51c57583d |
hex | 30e61757f |
13126169983 has 2 divisors, whose sum is σ = 13126169984. Its totient is φ = 13126169982.
The previous prime is 13126169977. The next prime is 13126169993. The reversal of 13126169983 is 38996162131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13126169983 - 25 = 13126169951 is a prime.
It is a super-2 number, since 2×131261699832 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13126169933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563084991 + 6563084992.
It is an arithmetic number, because the mean of its divisors is an integer number (6563084992).
Almost surely, 213126169983 is an apocalyptic number.
13126169983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126169983 is an equidigital number, since it uses as much as digits as its factorization.
13126169983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 419904, while the sum is 49.
The spelling of 13126169983 in words is "thirteen billion, one hundred twenty-six million, one hundred sixty-nine thousand, nine hundred eighty-three".
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